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public IEnumerable<double> GenerateLogNormalDistribution(int numberOfTimes, double mean, double standardDeviation) { Random random = new Random(); ...
C# On Lognormal Distribution
by Jonathan,
January 29, 2008 22:43
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public List<double> GenerateLogNormalDistribution(int numberOfTimes, double mean, double standardDeviation) { Random randomGenerator = new Random(); ...
C# Lognormal Distribution
Is there a better way to do...
I refactored my own code......